As user3251498 has pointed out, you must hit CTRL + H to bring up the Find and Replace dialog. NB: These Replace options are not accessible via the Find interface in the Navigation sidebar that pops up when you hit CTRL+F. matches every character except a new line, so you need to do something like this:j2 <- strremoveall(j, Footnotes(. I do believe that section breaks are matched by m ('Page/Section break'), however. I am trying to remove all parts of a string beginning with (and including) the word Footnotes in the following example but its not.1 answer Top answer: Hi, StatSteph. Neither ^l ('Manual line break'), ^n ('Column break'), will catch regular old newlines (like, the kind you enter when you press, well, the ENTER key. If you're using Word's version of regular expression (regex/regexp) syntax (enabled by checking the box labeled 'Use wildcards' in the Find and Replace dialog*), then newlines are matched by ^13 (which I suppose is equivalent to ^p, 'Paragraph mark', which Find/Replace only accepts when 'Use wildcards' is not selected. The answer (for those running later versions of Word) I'm running Word 2016, and the only alternative to the basic literal searching (with a few special character escapes) is 'Wildcard' matching, which is. The screenshot below is an example of replacing newlines with asterisks as. Unfortunately, it seems that Microsoft has since ditched regexp in favor of its own 'Wildcard' syntax. The word delete or remove can be misleading as Spark is lazy evaluated. According to this answer to a question on StackOverflow, Word versions '97-2013 used regular regexp syntax (pun intended). Click Replace All and click OK when Word tells you it has done the replacement.

Replace carriage return in word